1(x)=x^2+2

Solution for 1(x)=x^2+2 equation:

Simplifying
1(x) = x2 + 2

Reorder the terms:
1x = 2 + x2

Solving
1x = 2 + x2

Solving for variable 'x'.

Reorder the terms:
-2 + 1x + -1x2 = 2 + x2 + -2 + -1x2

Reorder the terms:
-2 + 1x + -1x2 = 2 + -2 + x2 + -1x2

Combine like terms: 2 + -2 = 0
-2 + 1x + -1x2 = 0 + x2 + -1x2
-2 + 1x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 1x + -1x2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
2 + -1x + x2 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -1x + -2 + x2 = 0 + -2

Reorder the terms:
2 + -2 + -1x + x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x + x2 = 0 + -2
-1x + x2 = 0 + -2

Combine like terms: 0 + -2 = -2
-1x + x2 = -2

The x term is -1x.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1x + 0.25 + x2 = -2 + 0.25

Reorder the terms:
0.25 + -1x + x2 = -2 + 0.25

Combine like terms: -2 + 0.25 = -1.75
0.25 + -1x + x2 = -1.75

Factor a perfect square on the left side:
(x + -0.5)(x + -0.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.